(16x)^2+(9x)^2=(55)^2

Solution for (16x)^2+(9x)^2=(55)^2 equation:

(16x)^2+(9x)^2=(55)^2

We move all terms to the left:

(16x)^2+(9x)^2-((55)^2)=0

determiningTheFunctionDomain
16x^2+9x^2-55^2=0

We add all the numbers together, and all the variables

25x^2-3025=0

a = 25; b = 0; c = -3025;
Δ = b2-4ac
Δ = 02-4·25·(-3025)
Δ = 302500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{302500}=550$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-550}{2*25}=\frac{-550}{50}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+550}{2*25}=\frac{550}{50}
=11
$